You start with 0001 and count your way up to 9999.
There's a good reason that they're not listed here for you. There are quite
a goodly number of them. Let's figure out how many there are, shall we ?
.0001 to .9999 . . . . . 9,999 numbers
1.001 to 9.999 . . . . . 8,999 numbers
10.01 to 99.99 . . . . . 8,999 numbers
100.1 to 999.9 . . . . . 8,999 numbers
1000 to 9999 . . . . . . 9,000 numbers
Total . . . . . 45,996 numbers that require 4 digits
The answer is 3,584. The first digit of the four-digit number can be one of seven figures: 1,2,4,5,7,8 or 9 (if it is 0, then you don't have a four-digit number!) Each of the remaining digits can be one of eight figures: 1,2,4,5,7,8,9 or 0. The number of possible combinations is therefore 7 x 8 x 8 x 8 = 3,584.
9999
If you include 0000, ten thousand unique four digit codes are possible.
9,876
9876
The answer is 3,584. The first digit of the four-digit number can be one of seven figures: 1,2,4,5,7,8 or 9 (if it is 0, then you don't have a four-digit number!) Each of the remaining digits can be one of eight figures: 1,2,4,5,7,8,9 or 0. The number of possible combinations is therefore 7 x 8 x 8 x 8 = 3,584.
There are four significant figures in 3001.
9999
Add the two greatest possible four digit numbers. 9999 + 9999
There are four significant figures in the measurement 77.09 meters. Each non-zero digit and any zeros between them are considered significant.
To correct to 4 significant figures, you need to round the number to have four digits starting with the first non-zero digit from the left. If the fifth digit is 5 or more, round up the last remaining digit. If it's less than 5, keep the digit as it is.
There are four significant figures in the number 2603000. Zeros at the end of a number are considered significant if they are to the right of the decimal point or if they are after a non-zero digit.
If you include 0000, ten thousand unique four digit codes are possible.
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
5040
1221
9,876