x=20 y=-3
To find the intercepts of the equation (-3x + 5y - 2z = 60), we can set two variables to zero and solve for the third. x-intercept: Set (y = 0) and (z = 0): (-3x = 60 \Rightarrow x = -20) (intercept at ((-20, 0, 0))). y-intercept: Set (x = 0) and (z = 0): (5y = 60 \Rightarrow y = 12) (intercept at ((0, 12, 0))). z-intercept: Set (x = 0) and (y = 0): (-2z = 60 \Rightarrow z = -30) (intercept at ((0, 0, -30))). Thus, the intercepts are ((-20, 0, 0)), ((0, 12, 0)), and ((0, 0, -30)).
3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
3x/(5-x)/3=4 3x/(5-x)=4X3 3x=12(5-x) 3x=60-12x 3x+12x=60 x=4
3x + 15 = 603x = 60 - 153x = 45x = 45/3Therefore, x = 15.
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The intercept of -3x + 5y - 2z = 60 are (-20, 0, 0), (0, 12, 0) and (0, 0, -30).
To find the intercepts of the equation (-3x + 5y - 2z = 60), we can set two variables to zero and solve for the third. x-intercept: Set (y = 0) and (z = 0): (-3x = 60 \Rightarrow x = -20) (intercept at ((-20, 0, 0))). y-intercept: Set (x = 0) and (z = 0): (5y = 60 \Rightarrow y = 12) (intercept at ((0, 12, 0))). z-intercept: Set (x = 0) and (y = 0): (-2z = 60 \Rightarrow z = -30) (intercept at ((0, 0, -30))). Thus, the intercepts are ((-20, 0, 0)), ((0, 12, 0)), and ((0, 0, -30)).
-57
3x^2+3x-60=3(x^2+x+20)=3(x+5)(x-4)
180 = 3 x 60
3x/(5-x)/3=4 3x/(5-x)=4X3 3x=12(5-x) 3x=60-12x 3x+12x=60 x=4
6x2+6xy-3x
plot 4y then 3x
60%
3x + 15 = 603x = 60 - 153x = 45x = 45/3Therefore, x = 15.
3x = 60 Divide both sides by 3 to find the value of x: x = 20
Points: 0 2 and 6 0 Equation: y = -1/3x+2