The intercept of -3x + 5y - 2z = 60 are (-20, 0, 0), (0, 12, 0) and (0, 0, -30).
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3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
Because of the limitations of the question software, it was not possible to determine what the original equation was supposed to be, so we assumed it is 3x + 5y = 7. It could have just as easily been 3x - 5y = 7, or even 3x/5y = 7.So, let's solve them all for x.3x + 5y = 73x = 7 - 5yx = (7 - 5y)/3How about 3x - 5y = 7?3x - 5y = 73x = 7 + 5yx = (7 + 5y)/3And 3x/5y = 7?3x/5y = 73x = 35yx = 35y/3 Solving for y The above equations wrote the equation so that x is a function of y, not the other way around. Here's how to rewrite the equation so that y is a function of x: 3x + 5y = 7 5y = -3x + 7 y = (-3x + 7)/5
X intercept is the value of X when Y = 0 -5Y + 3X = 12 ley Y = 0 3x = 12 x = 4
3x + 5y = -1 2x - 5y = 16 Add the two equations: 5x = 15 or x = 3 Substitute for x in the first equation: 3*3 + 5y = -1 15 + 5y = -1 5y = -10 so y = -10/5 = -2 The solution is (x, y) = (3, -2)
x = 1, y = 0