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An expression of the second degree can be any kind of expression, the most popular being a quadratic polynomial of the form ax^2 + bx + c.
F(x) = 15x2 - 2.5 + 3 That's a quadratic or 2nd degree polynomial in x.
what kind of polynomial is shown 3x3+x+1
I really want to see x^3 to represent x to the power of 3 and x3 to represent the third element of the sequence (xn). Because in Calculus, we use x3, a5, etc. all the time. Anyway 3x^3 + x + 1 is a degree 3 (highest degree in the poly.) polynomial.
I am assuming this is: .2x4 - 5x2 - 7x, which would be a Quartic Polynomial.
monomial,binomial, trinomial, quadrinomial and quintinomial
A fifth degree polynomial.
An expression of the second degree can be any kind of expression, the most popular being a quadratic polynomial of the form ax^2 + bx + c.
F(x) = 15x2 - 2.5 + 3 That's a quadratic or 2nd degree polynomial in x.
what kind of polynomial is shown 3x3+x+1
It is a monomial.
I really want to see x^3 to represent x to the power of 3 and x3 to represent the third element of the sequence (xn). Because in Calculus, we use x3, a5, etc. all the time. Anyway 3x^3 + x + 1 is a degree 3 (highest degree in the poly.) polynomial.
I am assuming this is: .2x4 - 5x2 - 7x, which would be a Quartic Polynomial.
There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24There are many possible answers. But given 5 points, an answer that can be guaranteed is that it is a polynomial of degree 4 (a quartic).In this case, Un = (-13n4 + 166n3 - 719n2 + 1310n - 720)/24
Actually, the roots of a Hurwitz polynomial are in the left half of the complex plain, not on the imaginary axis. As for the reason, that is because the polynomial is DEFINED to be one that has that kind of roots.
If you mean: 3x+2y = 3 then it is a straight line equation
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