Although there are no reasons to support such an assumption, suppose the shape is a rectangle. Then perimeter = 2*(Length + Width) 70 = 2*(2 + width) 35 = 2 + width 33 = width. ie Width = 33 feet. Normally a length is larger than its width. It is therefore more than likely that the shape is not a rectangle and the above is based on an incorrect assumption.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
length = area ÷ width = 132 cm2 ÷ 4 cm = 33 cm
Answer: .33 acre = 14,374.8 ft²
The perimeter is: 9.6+6.9+9.6+6.9 = 33 miles
Area of a rectangle: length times width Width=11 Length= 11x3= 33 11x33= 363 square feet
Although there are no reasons to support such an assumption, suppose the shape is a rectangle. Then perimeter = 2*(Length + Width) 70 = 2*(2 + width) 35 = 2 + width 33 = width. ie Width = 33 feet. Normally a length is larger than its width. It is therefore more than likely that the shape is not a rectangle and the above is based on an incorrect assumption.
volume equals length times width times height = 33 x 24 x 24
Meter is a unit of length. acre is a unit of area. You can not convert meters to acres. You can convert hectares to acres.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
Let the length be 3x+2 and the width be x: (3x+2)*x = 33 3x2+2x = 33 3x2+2x-33 = 0 Solve as a quadratic equation: (3x+11)(x-3) = 0 Therefore: x = -11/3 or x = 3 The dimensions can't be negative so x must = 3 So: length = 11 feet and width = 3 feet
There are approximately 2.5 satak in .33 acre.
length = area ÷ width = 132 cm2 ÷ 4 cm = 33 cm
Let the width be x:- If: 2(x+2) = 70 feet Then: x = 33 feet Check: 2(33+4) = 70 feet
Answer: .33 acre = 14,374.8 ft²
Yes, it is less than half an acre. Half an acre would be shown as .5 acres.
The perimeter is: 9.6+6.9+9.6+6.9 = 33 miles