42 for sure...
364
The two numbers can be 5 times 8 = 40
The two whole numbers that go into 40 evenly are 1, 2, 4, 5, 8, 10, 20, and 40.
1 x 5 = 5 5 x 10 = 50 ; 10 is 5+5 50 x 20 = 1000; 20 is 10+10 1000 x 40 = 40,000 ; 40 is 20 + 20 40,000 x 80 = 3,200,000; 80 is 40+40 therefore the next 2 numbers are 40,000 and 3,200,000
42 for sure...
364
The difference between the numbers is increasing by 1 each time. Therefore, the next two numbers in the sequence are 40 - 5 = 35 and 35 - 6 = 29.
Well, isn't that just a happy little math problem we have here! Let's see, if the highest common factor is 8, then the two numbers must both be multiples of 8. And if the lowest common multiple is a multiple of 5, then the two numbers must also be multiples of 5. So, the two numbers Niamh is thinking of are 40 and 80. Happy calculating!
70, 112, 168
How about 40 and 1.
The two numbers can be 5 times 8 = 40
The two whole numbers that go into 40 evenly are 1, 2, 4, 5, 8, 10, 20, and 40.
1 x 5 = 5 5 x 10 = 50 ; 10 is 5+5 50 x 20 = 1000; 20 is 10+10 1000 x 40 = 40,000 ; 40 is 20 + 20 40,000 x 80 = 3,200,000; 80 is 40+40 therefore the next 2 numbers are 40,000 and 3,200,000
-1540
72 and 40
40 and 72