n(n-3)/2 n - number of sides
...or an easy way for thickos that dont understand algebra forumals : n-3 x n / 2
It is: 0.5*(10 squared - (3*10)) = 35 diagonals
A convex decagon has 10 sides. The formula for calculating the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a decagon, substituting ( n = 10 ) gives ( \frac{10(10-3)}{2} = \frac{10 \times 7}{2} = 35 ). Therefore, a convex decagon has 35 diagonals.
decagon
35
A decagon has 10 sides and 35 diagonals
It is: 0.5*(10 squared - (3*10)) = 35 diagonals
There are 35 diagonals in a 10 sided decagon
A convex decagon has 10 sides. The formula for calculating the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a decagon, substituting ( n = 10 ) gives ( \frac{10(10-3)}{2} = \frac{10 \times 7}{2} = 35 ). Therefore, a convex decagon has 35 diagonals.
A tetra-decagon is a 14 sided polygon having 77 diagonals
8
decagon
35.
35
35
A decagon has 10 sides and 35 diagonals
A decagon has 35 diagonals. This can be computed by multiplying ten by seven and dividing by two. Seven is derived from the number of sides minus three.
35 diagonals