Possibilities on the first toss = 2. For each of these . . .
Possibilities on the second toss = 2. Fo reach of these . . .
Possibilities on the third toss = 2.
Total possible sequances in 3 tosses = 2 x 2 x 2 = 8.
Number of ways to get heads exactly twice = 3 .
H - H - T
H - T - H
T - H - H
Probability of exactly 2 heads in 3 tosses = 3/8 = 37.5% .
Odds = 3 in 8, or 5 to 3 against it.
They are HHT HTH and THH
suppose you flipped a coin 100 times you might have flipped heads 50 time and tails 50 times
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
The relative frequency of an event is calculated by dividing the number of times the event occurs by the total number of trials. In this case, the coin was flipped 5 times and heads appeared 2 times. Therefore, the relative frequency of getting heads is 2 (heads) divided by 5 (flips), which equals 0.4 or 40%.
25%
7/8
They are HHT HTH and THH
suppose you flipped a coin 100 times you might have flipped heads 50 time and tails 50 times
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
It is 4*(1/2)4 = 4/16 = 1/4
The relative frequency of an event is calculated by dividing the number of times the event occurs by the total number of trials. In this case, the coin was flipped 5 times and heads appeared 2 times. Therefore, the relative frequency of getting heads is 2 (heads) divided by 5 (flips), which equals 0.4 or 40%.
1 and a half
25%
The probability of flipping a fair coin four times and getting four heads is 1 in 16, or 0.0625. That is simply the probability of one head (0.5) raised to the power of 4.
If a coin is flipped 4 times, the probability of getting 3 heads is: 4C3 (1/2)^3 (1/2)^1 = 4(1/8)(1/2) = 4/16 = 1/4
To find the probability of getting exactly two heads when tossing a coin three times, we first determine the total number of possible outcomes, which is (2^3 = 8). The favorable outcomes for getting exactly two heads are: HHT, HTH, and THH, totaling 3 outcomes. Therefore, the probability of getting exactly two heads is ( \frac{3}{8} ).
About a 1 in 16 chance of getting a coin to land on heads 4 times in a row.