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If: 3x-2y = 1 and 3x^2-2y^2+5 = 0

Then by rearranging: 3x = 2y+1 and y^2-2y-8 = 0

Solving the above quadratic equation: y = 4 or y = -2

Bu substitution points of intersection are: (3, 4) and (-1, -2)

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