If: 3x-2y = 1 and 3x^2-2y^2+5 = 0
Then by rearranging: 3x = 2y+1 and y^2-2y-8 = 0
Solving the above quadratic equation: y = 4 or y = -2
Bu substitution points of intersection are: (3, 4) and (-1, -2)
Points of intersection work out as: (3, 4) and (-1, -2)
The points of intersection are: (7/3, 1/3) and (3, 1)
4
Yes. 6 squared+71 squared equals 5077
Improved Answer:-If: 2x+y = 5 and x^2 -y^2 = 3Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0Solving the above quadratic equation: x = 2 and x = 14/3By substitution points of intersection are: (2, 1) and (14/3, -13/3)
Points of intersection work out as: (3, 4) and (-1, -2)
It is the Cartesian equation of an ellipse.
The points of intersection are: (7/3, 1/3) and (3, 1)
4
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
Yes. 6 squared+71 squared equals 5077
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
The points are (-1/3, 5/3) and (8, 3).Another Answer:-The x coordinates work out as -1/3 and 8Substituting the x values into the equations the points are at (-1/3, 13/9) and (8, 157)
Improved Answer:-If: 2x+y = 5 and x^2 -y^2 = 3Then by rearranging: y = 5 -2x and -3x^2 -28+20x = 0Solving the above quadratic equation: x = 2 and x = 14/3By substitution points of intersection are: (2, 1) and (14/3, -13/3)
They intersect at the point of: (-3/2, 11/4)
No, in the Cartesian coordinate system it would show a vertical line whose intersection of the x-axis is 4.
The 2 stands for squared . So in all the formula is : Energy equals the mass times the constant (Speed of light) squared. The 2 squares the formula.