0
More values are required to solve this question since there are only two unknowns given. To solve this equation, there has to be only a single unknown value. In this example, assuming x is 0,
0 = y2 + 2y
0 = y (y+2)
y = 0 or y+2 = 0
y = 0 pr y = -2
Therefore, in this case, the points of intersection are (0,0) and (0,-2)
If x=y
Y = y2 + 2y
0 = y2 + y
0 = y(y+1)
y = 0 or y+1 = 0
y = 0 or y=-1
When y=0
x=0
When y=-1
x=-1
Therefore, in this case, the points of intersection are (0,0) and (-1,-1)
Note: to solve quadratic equations, cubic equations or any equation with any unknowns not to the power of 1, you must get a value of 0 on one side of the equation before you can get the final values.
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What are the points of intersection of y equals x squared plus 2x plus 2 with y equals x cubed plus 2?
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
What are the point of intersection of x is equal to y squared plus 2y?
You need two, or more, curves for points of intersection.
What is the point of intersection of the parabolas of y equals 3x squared plus 10x plus 11 and y equals 2 -2x -x squared?
They intersect at the point of: (-3/2, 11/4)
What are the points of intersection of x plus y equals 7 with x squared plus y squared equals 25 showing key stages of work?
If: x+y = 7 and x2+y2 = 25 Then: x = 7-y and so (7-y)2+y2 = 25 => 2y2-14y+24 = 0 Solving the quadratic equation: y = 4 and y = 3 By substitution points of intersection: (3, 4) and (4, 3)
What are the coordinates for x2 plus y2 equals 185 and x plus y equals 17?
We believe that those equations have no real solutions, and that their graphs therefore have no points of intersection.
