If you are Canadian (no joke), there are 618(101559956668416) ways. If you are american, there are 518(3814697265652) ways. Hope this helps!
Jasmine puts 18 hats away she puts a eq number of hats on 3 shelves
> 6.40237371 × 1015Actually, since there are four i's and two o's, the number of distinct permutations of the letters in "oversimplification" is 18!/(4!2!) = 133,382,785,536,000.
You, can't.
if order of beads matters than you get 18P12= 8.892185702*1012. if order doesn't matter than it's 18C12= 18564 ways to arrange the beads.
Think of the chairs as arrays. The dimensions of the arrays give you the factors of 18.
You can only do multiplation so a whole number is divisble by another whole number when the quotient is a whole number and the remainder is 0
If you are Canadian (no joke), there are 618(101559956668416) ways. If you are american, there are 518(3814697265652) ways. Hope this helps!
Oh, what a happy little question! When you have an array for 2 times 9, you can see 2 rows of 9, which equals 18. And when you have an array for 5 times 9, you can see 5 rows of 9, which equals 45. Keep exploring those arrays and you'll create a beautiful landscape of multiplication facts!
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
Assuming you want a rectangular array, 1 x 18, 2 x 9, or 3 x 6.
The multiplication fact (singular, not plural 'facts') that can be found is 7x9 = 63. Using the arrays, a 2x9 array (2 rows of 9 items) and 5x9 array (5 rows of 9 items) is 63: 2x9 = 18 5x9 = 45 18 + 45 = 63
36 x 1 18 x 2 12 x 3 9 x 4 6 x 6
Jasmine puts 18 hats away she puts a eq number of hats on 3 shelves
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
> 6.40237371 × 1015Actually, since there are four i's and two o's, the number of distinct permutations of the letters in "oversimplification" is 18!/(4!2!) = 133,382,785,536,000.
You, can't.