55
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3 cm, 4 cm and 5 cm because they are a Pythagorean triple
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.