3 cm, 4 cm and 5 cm because they are a Pythagorean triple
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.
15 cm and 36 cm
3 cm, 4 cm and 5 cm because they are a Pythagorean triple
A box has no equation. There are different equations for its volume, its surface area, the longest (principal) diagonal.
Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7
The correct answer is 10 times the square of 2. You must use the Pythagorean Theorem, which is a2+b2=c2. The sides if the square measure 10 cm because adding all four sides will give you the perimeter of 40 cm. Replace a and b with 10 and solve for c.
The diagonal works out as length of 33.3 cm or 333 mm To solve this you need to apply the equations for the area of a rectangle (a x b) and the perimeter of a rectangle (2a + 2b) as well as the Pythagorean Theorem (a^2 + b^2 = c^2).
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
Diags of rhombus form 4 Pythagorean triangles. If these triangles sides are 10 and 8 cm then hypotenuses would be 12.8 cm. Each hypotenuse is one side of the rhombus so perimeter would be 51.2 cm to nearest mm.
You learn the Pythagorean theorem.
It depends if its a baby snail or a large male snail. I can't fine a good enough website so if you don't know ask your friends and family but I think they can go from 1 cm from top the bottom and 5 or 4 cm. I honestly not have a clue!
Total distance 10 m. Distance travelled 0.15 + 0.112 = 0.262, leaving 9.738 m to go
Let its length be 3x+4 and its width be x Perimeter: 2*(3x+4+x) = 88 Solving the equation x = 10 Therefore: length = 34 cm and width = 10 cm Check: 2*(34+10) = 88 cm