The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
Diagonal = 10 meters.
If the diagonal is 25m and the area is 168m2 then the longest edge of the rectangle will be 24m.
30 ft
Width is 5.
About 12.7. (I got it from using the pythagreon theyrom.)
15 cm for the diagonal.
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with lengths of 10 cm and 15 cm, the diagonal (d) can be calculated as (d = \sqrt{10^2 + 15^2}). This simplifies to (d = \sqrt{100 + 225} = \sqrt{325}), which is approximately 18.03 cm. Thus, the length of the diagonal is about 18.03 centimeters.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
The length of the diagonal is about 16.03 feet.
The diagonal is 26cm
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
The diagonal length is about 18.44 inches.
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
This length (diagonal) = sq.rt ( l2 + b2 ) where 'l' is length of the rectangle and 'b' is the breadth of the rectangle.
18.9 feet