Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7
"X" = .66
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
Approximately 15.62 feet.
D2 = (57)2 + (24.5)2 = (3,249) + (600.25) = 3,849.25D = sqrt(3,849.25) = 62.0423 (rounded)
what is the perimeter and area of a rectangle 3cm long and 3cm wide
"X" = .66
The diagonal would be 12.53 meters.
The diagonal is 3.231 meters.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
15 cm for the diagonal.
According to the given length & width, the diagonal must be 15 cm.So,2X - 11 = 152X = 26X = 13
To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m
Approximately 15.62 feet.
15 inches (solved with the help of Pythagoras' theorem)
Using Pythagoras' theorem it is 26 inches in length
120 inches (by finding the hypotenuse of a right triangle).
D2 = (57)2 + (24.5)2 = (3,249) + (600.25) = 3,849.25D = sqrt(3,849.25) = 62.0423 (rounded)