To find the solutions of the equation (2x^2 + 8x + 26 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}), where (a = 2), (b = 8), and (c = 26). First, we calculate the discriminant: (b^2 - 4ac = 8^2 - 4(2)(26) = 64 - 208 = -144). Since the discriminant is negative, the equation has no real solutions, but two complex solutions given by (x = -4 \pm 6i).
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5
To find the number of solutions to the equation (8x + 11 = 8x + 8), we can simplify it by subtracting (8x) from both sides, resulting in (11 = 8). This is a false statement, indicating that there are no values of (x) that can satisfy the equation. Therefore, there are zero solutions to this equation.
To find the solutions of the equation (2x^2 + 8x + 26 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}), where (a = 2), (b = 8), and (c = 26). First, we calculate the discriminant: (b^2 - 4ac = 8^2 - 4(2)(26) = 64 - 208 = -144). Since the discriminant is negative, the equation has no real solutions, but two complex solutions given by (x = -4 \pm 6i).
2x2 = 8x x = 8x/2x x = 4 Check: 2(4)2 = 8(4) 2(16) = 32 32 = 32
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
y=-2x^2+8x+3
-1/2
If you mean 2x times -2x then it would be -8x.
2(x + 3)(x + 1)
Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5
To find the number of solutions to the equation (8x + 11 = 8x + 8), we can simplify it by subtracting (8x) from both sides, resulting in (11 = 8). This is a false statement, indicating that there are no values of (x) that can satisfy the equation. Therefore, there are zero solutions to this equation.
If you mean: x2+8x-9 = 0 then the solutions are x = 1 and x = -9
2x2 is 4, so if 4=8x then x=1/2. 1/2 times 8 is the same as 8 divided by 2 (8/2), which simplifies to 4/1, or 4. So x=1/2.
2x2 - 3 = 13 So 2x2 = 16 x2 = 8 So that x = ±2√2