the solutions to this equation are -1,+1 and -3.
you can solve this equation by using the polynomial long division method. we basically want to factorize this and polynomial and equate its factors to zero and obtain the roots of the equation. By hit and trial , it clear that x=1 i.e is a root of this equation. So (x-1) should be a factor of the given polynomial (LHS). Divide the polynomial by x-1 using long division method and you will get the quotient as x2+4x+3 and remainder would be 0 ( it should be 0 as we are dividing the polynomial with its factor. Eg when 8 is divided by any of its factor like 4,2 .. remainder is always zero )
Now, we can write the given polynomial as product of its factors as
x3+3x2-x-3 = (x-1)(x2+4x+3)
=(x-1)(x+1)(x+3) [by splitting middle term method]
so the solutions for the given polynomial are obtained when RHS = 0, Hence x=-1 , X = +1, x=-3 are the solutions for this equation.
No. It's a quadratic equation, and it has two solutions.
2 this Domo
One.
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.
one
There are 120 solutions.
There are no real solutions because the discriminant of the quadratic equation is less than zero.
It is a quadratic equation and its solutions can be found by using the quadratic equation formula.
No. It's a quadratic equation, and it has two solutions.
1
no
2 this Domo
One.
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.
one
It is a quadratic equation that has 2 solutions
x = 2 and x = -5