y - x = 5 so:
x = 1, y = 6 and all increments (and decrements) of 1 in each term, so there are an infinite number of solutions.
There are a number of possible solutions which will have x=2 and y = 10 as solutions but many of them will also allow other solutions. One possibility, with a unique solution, is (x-2)2 + (y-10)2 = 0
x2-10 = 0 x2 = 10 x = the square root of 10
There are no solutions because the discriminant of this quadratic equation is less than zero
200/2 , 10^2, etc. there are an infinite number of solutions.
The equation has infinitely many solutions.
There are a number of possible solutions which will have x=2 and y = 10 as solutions but many of them will also allow other solutions. One possibility, with a unique solution, is (x-2)2 + (y-10)2 = 0
x2-10 = 0 x2 = 10 x = the square root of 10
No solutions appear on the list that accompanies the question.
There are no solutions because the discriminant of this quadratic equation is less than zero
The equation has infinitely many solutions.
200/2 , 10^2, etc. there are an infinite number of solutions.
There is an infinite number of solutions because x is not determined.
x = -5 x = 2
Yes and their solutions are x = 41 and y = -58
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
The person or program that solves the equation does.
If: n squared -n -90 = 0 Then the solutions are: n = 10 or n = -9