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If you mean: x^2 -4x +20 = 0 then it has no real solutions because its discriminant is less than zero.
This has an infinite number of solutions. Take any two non-zero numbers; e.g. 5 and -3, and divide 20 by both to get the third number, e.g. 20 / 5 / (-3) = 4 / (-3) = -4/3.This has an infinite number of solutions. Take any two non-zero numbers; e.g. 5 and -3, and divide 20 by both to get the third number, e.g. 20 / 5 / (-3) = 4 / (-3) = -4/3.This has an infinite number of solutions. Take any two non-zero numbers; e.g. 5 and -3, and divide 20 by both to get the third number, e.g. 20 / 5 / (-3) = 4 / (-3) = -4/3.This has an infinite number of solutions. Take any two non-zero numbers; e.g. 5 and -3, and divide 20 by both to get the third number, e.g. 20 / 5 / (-3) = 4 / (-3) = -4/3.
The solutions are: x = 4, y = 2 and x = -4, y = -2
(x + 5)(x - 20) x + 5 = 0 x - 20 = 0 x = -5, 20
solutions of the equation: x2-x=20