Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
2NaH2 + O2 yields 2Na + 2H2O
The binding of Na+ ions to the pump
P + Na(OH) + H20 = NaH2PO2 + PH3
0
Na+ and Cl- are spectator ions.
Na+, K+,Li+, NH4 + and NO3 - are always spectator ions because they are always soluble
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
Na+ and Cl-
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
Yes, sodium ions (Na+) are often considered spectator ions in chemical reactions because they do not actively participate in the reaction, but rather remain in the solution without being consumed or changed.
The spectator ions in this reaction are Na+ and NO3-. They remain unchanged on both sides of the equation and do not participate in the formation of the precipitate AgI.
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.
When sodium bicarbonate (NaHCO3) is added to water (H2O), it dissociates into sodium ions (Na+), bicarbonate ions (HCO3-), and water. This reaction releases hydrogen ions (H+) as bicarbonate ions act as a weak acid in water.
K+ and NO3- because KOH + HNO3 (yields) H2O + KNO3