1.square the first term
2.square the second term
3.square the last tem
give me something to answer and ill answer it ASAP.. :D but here is my example 2 2 (a+b) (a-b) =a -b
To solve a binomial expression, you typically simplify or factor it. If you're solving an equation set to zero, you can use methods like factoring, completing the square, or applying the quadratic formula if it's a quadratic binomial. For binomials, you may also apply the difference of squares or the sum/difference of cubes formulas if applicable. Always ensure to check your solutions by substituting them back into the original expression.
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
To get the product, multiply the first number by the second. To get the sum, add the second number to the first. To get the difference, subtract the smaller number from the larger.
The ones that are the sum or the difference of two terms.
a²-b²
Binomials are algebraic expressions of the sum or difference of two terms. Some binomials can be broken down into factors. One example of this is the "difference between two squares" where the binomial a2 - b2 can be factored into (a - b)(a + b)
There are many different methods to factor polynomials in general; specifically for binomials, you can check:whether you can separate a common factor,whether the binomial is the difference of two squares,whether the binomial is the sum or difference of two cubes (or higher odd-numbered powers)
Binomials are algebraic expressions of the sum or difference of two terms. Some binomials can be broken down into factors. One example of this is the "difference between two squares" where the binomial a2 - b2 can be factored into (a - b)(a + b)
give me something to answer and ill answer it ASAP.. :D but here is my example 2 2 (a+b) (a-b) =a -b
underline numbers and do the sum with those numbers
0
To solve a binomial expression, you typically simplify or factor it. If you're solving an equation set to zero, you can use methods like factoring, completing the square, or applying the quadratic formula if it's a quadratic binomial. For binomials, you may also apply the difference of squares or the sum/difference of cubes formulas if applicable. Always ensure to check your solutions by substituting them back into the original expression.
Well, honey, first you multiply the sum and difference of the two terms to get the difference of squares. Then you factor that bad boy into two binomials. Finally, you just simplify and voila, you've solved the product of sum and difference of two terms. Easy peasy, lemon squeezy!
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.