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What are the steps on solving for sum and difference of binomials?
1.square the first term 2.square the second term 3.square the last tem
Is (a-3) a the sum of two terms?
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
What is a method for multiplying two binomials?
Depends on the kind of binomials. Case 1: If both binomials have different terms, then use the distribution property. Each term of one binomial will multiply both terms of the other binomial. After distribution, combine like terms, and it's done. Case 2: If both binomials have exactly the same terms, then work as in the 1st case, or use the formula for suaring a binomial, (a ± b)2 = a2 ± 2ab + b2. Case 3: If both binomials have terms that only differ in sign, then work as in the 1st case, or use the formula for the sum and the difference of the two terms, (a - b)(a + b) = a2 - b2.
How do you write two binomials whose product is a difference of squares?
The two binomials can be written as (x - a)(x + a), for any constant a. Proof: Expand using FOIL: (x - a)(x + a) = x2 + xa - xa - a2 Group: (x - a)(x + a) = x2 - a2 x2 - a2 is a difference of squares. Thus, the product of (x - a) and (x + a) is a difference of squares.
Is sum and difference the same?
No. The sum is the answer to an addition problem. The difference is the answer to a subtraction problem.
