You should be able to look at that and realize . . .
--> y = 4
--> The graph is a horizontal line.
--> It doesn't cross the x-axis anywhere.
--> 'y' is 4 at every point on the line, including the point
where it crosses the y-axis.
Wiki User
∙ 12y agox-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
X intercept: -5 Y intercept: +3
x = 0 and y = 4
When y is 0 then x intercept is at (10, 0) When x is 0 then y intercept is at (0, -12)
4x-5y+20 = 0 -5y = -4x-20 y = 4/5x+4 which is now in slope intercept form
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
2x+5y=20 Solve for y -2x -2x 5y=20-2x 5 5 5 y=4-2x 5
X intercept: -5 Y intercept: +3
x = 0 and y = 4
If you mean: 4x+5y=-20 then the y intercept is (0, -4) and x intercept is (-5, 0)
-3x + 5y = -15At the x-intercept, y=0:-3x = -15 . . . . . x = 5At the y-intercept, x=0:5y = -15 . . . . . y = -3
When y is 0 then x intercept is at (10, 0) When x is 0 then y intercept is at (0, -12)
The intercept of -3x + 5y - 2z = 60 are (-20, 0, 0), (0, 12, 0) and (0, 0, -30).
x + 5y = 0Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides.x = -5yThis is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero.The only place on the graph where that is true is the origin. So the line goes through the origin,and the 'x' and 'y' intercepts are both zero.
what is the solution of x-5y=10 and 2x-10y=20
4x-5y+20 = 0 -5y = -4x-20 y = 4/5x+4 which is now in slope intercept form