Three consecutive integers around 249 are 248, 249, and 250. Consecutive integers differ by one, so these numbers follow one another sequentially.
Let the three consecutive integers be ( x ), ( x+1 ), and ( x+2 ). The equation can be set up as ( x + (x + 1) + (x + 2) = 252 ). Simplifying this gives ( 3x + 3 = 252 ), which leads to ( 3x = 249 ) and ( x = 83 ). Therefore, the three consecutive integers are 83, 84, and 85.
The three integers are 25, 26, and 27.
The set of integers is divided into three subsets. One is the positive integers. Another is the negative integers. The last subset has one element -- zero. In sum, integers are composed of the positive integers, the negative integers, and zero.
The integers are -19, -18 and -17.
Three consecutive integers around 249 are 248, 249, and 250. Consecutive integers differ by one, so these numbers follow one another sequentially.
Let the three consecutive integers be ( x ), ( x+1 ), and ( x+2 ). The equation can be set up as ( x + (x + 1) + (x + 2) = 252 ). Simplifying this gives ( 3x + 3 = 252 ), which leads to ( 3x = 249 ) and ( x = 83 ). Therefore, the three consecutive integers are 83, 84, and 85.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
There is no set of three consecutive integers for 187.
249
The three integers are 25, 26, and 27.
The set of integers is divided into three subsets. One is the positive integers. Another is the negative integers. The last subset has one element -- zero. In sum, integers are composed of the positive integers, the negative integers, and zero.
The three integers are 187, 188 and 189.
The integers are -19, -18 and -17.
9240 is the product of the three consecutive integers 20, 21, and 22.
The largest is 73.
The integers are -1, 1 and 3.