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Three consecutive integers around 249 are 248, 249, and 250. Consecutive integers differ by one, so these numbers follow one another sequentially.

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1mo ago

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Let the three consecutive integers be ( x ), ( x+1 ), and ( x+2 ). The equation can be set up as ( x + (x + 1) + (x + 2) = 252 ). Simplifying this gives ( 3x + 3 = 252 ), which leads to ( 3x = 249 ) and ( x = 83 ). Therefore, the three consecutive integers are 83, 84, and 85.


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The three integers of 249 can refer to its prime factorization, which is (3), (83), and (1) (since every integer can be multiplied by (1)). In terms of digits, the three integers that make up 249 are (2), (4), and (9). If you're looking for a different interpretation, please clarify!