Three consecutive integers around 249 are 248, 249, and 250. Consecutive integers differ by one, so these numbers follow one another sequentially.
Let the three consecutive integers be ( x ), ( x+1 ), and ( x+2 ). The equation can be set up as ( x + (x + 1) + (x + 2) = 252 ). Simplifying this gives ( 3x + 3 = 252 ), which leads to ( 3x = 249 ) and ( x = 83 ). Therefore, the three consecutive integers are 83, 84, and 85.
There is no set of three consecutive integers for 106.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
There are no three consecutive odd integers who's sum equals 13.
The three integers of 249 can refer to its prime factorization, which is (3), (83), and (1) (since every integer can be multiplied by (1)). In terms of digits, the three integers that make up 249 are (2), (4), and (9). If you're looking for a different interpretation, please clarify!
There is no set of three consecutive integers for 187.
Three consecutive integers have a sum of 12. What is the greatest of these integers?
Let the three consecutive integers be ( x ), ( x+1 ), and ( x+2 ). The equation can be set up as ( x + (x + 1) + (x + 2) = 252 ). Simplifying this gives ( 3x + 3 = 252 ), which leads to ( 3x = 249 ) and ( x = 83 ). Therefore, the three consecutive integers are 83, 84, and 85.
There is no set of three consecutive integers for 106.
There is no set of three consecutive integers whose sum is 71.
The sum of three consecutive integers is -72
9240 is the product of the three consecutive integers 20, 21, and 22.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
There are no three consecutive odd integers who's sum equals 13.
That isn't possible. The three consecutive number are assumed to be integers; the sum of three consecutive integers is always a multiple of 3 (try it out).
The three integers of 249 can refer to its prime factorization, which is (3), (83), and (1) (since every integer can be multiplied by (1)). In terms of digits, the three integers that make up 249 are (2), (4), and (9). If you're looking for a different interpretation, please clarify!