52
if one number is 32 more than the other the remainder of the number must be the same for both. subtract 32 from 54. divide the result by 2 and add the 32 subracted to one of the values to give you the two numbers 11 and 43.
It only is 2
Divide both numbers by 16
Divide those numbers by their GCF, which is 32. You should get 3/4
12 = 1 and 32 = 9
52
The mean is the average of a set of numbers. To find the average, you must add all the numbers in the set and divide that number by however many numbers are present in the set. For this example, you need to add 32 and 4 and then divide that answer by two, which is 18 in this case.
if one number is 32 more than the other the remainder of the number must be the same for both. subtract 32 from 54. divide the result by 2 and add the 32 subracted to one of the values to give you the two numbers 11 and 43.
1, 2, 4, 8, 16, 32.
It only is 2
Divide the number 32 by successive prime numbers to get the factors until you cant divide any more numbers... 32/1=32 (factors are 1 and 32) 32/2=16 (factors are 2 and 16) 32/3=does not divide to be a whole number 32/4=8 (factors are 4 and 8) 32/5=does not divide to be a whole number 32/6=does not divide to be a whole number 32/7=does not divide to be a whole number Now you done with all the numbers you can. Therefore 1,32,2,16,4 and 8 are factors.
30
Divide both numbers by 16
Divide those numbers by their GCF, which is 32. You should get 3/4
Yes, by these numbers: 1, 2, 4, 8, 16, 32.
1, 2, 4, 8, 16, 32