Let the two numbers be x and y.
According to the question,
xy=16
so, x=16/y
x-y=12
16/y-y=12
or 16-y^2=12y
Or y^2+12y-16=0
Solving the quadratic equation, we do not get any integral values.
There's some mistake in the question.
-12
Any two numbers whose product is '1' are each others' reciprocals.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
19
There are infinitely many expressions that simplify to any particular number; for example: any two numbers which, when added, give 24, any two numbers whose difference is 24, any two numbers whose product is 24, etc.
-76 and 76 whose product is -5776.
11
-12
-5 * 5 = -25
17 and 53
12 x 2 = 24 12 - 2 = 10 The two numbers are therefore 2 and 12.
two prime numbers whose product is 141 = 3 & 47
Any two numbers whose product is '1' are each others' reciprocals.
It would be possible to find two numbers whose sum is 7, two others whose difference is 7,two others whose product is 7, and two others whose quotient is 7.But if you're looking for numbers that equal 7, then 7 is your only choice.
There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.There are no two primes whose product is 50.
find two positive numbers whose product is a maximum. 1.) the sum is s.
4 and 19 4 x 19 = 76 19 - 4 = 15