Wiki User
β 10y agoVolume: 1*x*y = 12 or as xy = 12
Area: (2*1*x)+(2*x*y)+(2*1*y) = 38 or as x+xy+y = 19
So: x+12+y = 19 => x+y = 7 and y = 7-x
So: x(7-x) = 12 => 7x-x2-12 = 0
Solving the quadratic equation: x = 3 or x = 4
Values by substitution: when x = 3cm then y = 4cm
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β 10y agoAssuming these are the dimensions of a cuboid, 13 square cm.
There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
There is not enough information to calculate the dimensions.
It is the sum of each of the six square faces. Each face has an area of s2 square units where s is the side length. So the total surface area is 6s2 square units.
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
Assuming these are the dimensions of a cuboid, 13 square cm.
Following are the formulas of cuboid. Let the dimensions of the cuboid be l (length), w(width) and h (height). Lateral surface area of the cuboid = perimeter of rectangular base x height = 2(l + w)h square units= 2h(l + w) square units; Total surface area (TSA) = 2 (lw + wh + hl); Volume of cuboid (V) = lwh. Length of diagonal of one side is √(l^2 + w^2), √(w^2 + h^2), √(h^2 + l^2) - depending upon side. Length of diagonal across the cuboid is √(l^2 + w^2 + h^2)
A square prism is always a cuboid.
There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.
There is not enough information to calculate the dimensions.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
A cuboid can have 2, 4 or 6 square faces.
For a cuboid, the total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.In the case of a cube, L = B = H and so the total surface area is 6*L^2 square units.
It is the sum of each of the six square faces. Each face has an area of s2 square units where s is the side length. So the total surface area is 6s2 square units.
You imagine the cuboid, (which will have 6 faces) and work out the dimension of the edges for each individual face (there will be pairs of opposite faces with identical dimensions):3 * 4 = 123 * 4 = 123 * 2 = 63 * 2 = 62 * 4 = 82 * 4 = 812 + 12 + 6 + 6 + 8 + 8 = 52So the surface area is 52 square units.
A square is a 2-dimensional figure, a cuboid is 3-dimensional.