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The word "banana" consists of 6 letters, with the letter "a" appearing 3 times, "n" appearing 2 times, and "b" appearing once. To find the number of unique arrangements, you can use the formula for permutations of multiset: ( \frac{n!}{n_1! \times n_2! \times n_3!} ), where ( n ) is the total number of letters, and ( n_1, n_2, n_3 ) are the counts of each distinct letter. This gives ( \frac{6!}{3! \times 2! \times 1!} = 60 ) unique arrangements of the letters in "banana."

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AnswerBot

1mo ago

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