0
To find the x-intercepts of the parabola described by the equation (x^2 + 4x - 12 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Here, (a = 1), (b = 4), and (c = -12). Calculating the discriminant (b^2 - 4ac) gives (16 + 48 = 64). Therefore, the x-intercepts are (x = \frac{-4 \pm 8}{2}), resulting in (x = 2) and (x = -6).
What else can I help you with?
How do you graph a parabola?
y=x2+4x+1
What is the equation of a parabola with the vertex of 2 -1?
3
Is x2 - 4x -12 prim?
No. x2 -4x - 12 = (x + 2)(x - 6)
How do you answer this algebra problem X2-4x-12?
x2-4x-12 = (x-6)(x+2) when factored
Find the x intercept or interceptss and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
-2, 6
What are the x intercepts of the parabola x2 plus 4x minus 12?
x=2,-6 x^2+4x-12 (x^2-2x)(+6x-12) x(x-2)+6(x-2) (x-2)(x+6)=0
How do you factor x2 plus 4x-96?
x2 + 4x - 96 = (x - 8)(x + 12).
What is the vertex form of y equals x2 plus 4x - 7?
The vertex of the positive parabola turns at point (-2, -11)
What is the solution set for x2-4x equals 8?
x2 - 4x = 8 x2 - 4x + 4 = 8 + 4 (x - 2)2 = 12 x - 2 = +&- sq. root of 12 x = 2 +&- 2(sq. root of 3)
What is 4x-x2?
4x-x2 = 2
What is x to the second power plus 4x-12?
x2+4x-12 = (x-2)(x+6) when factored
What is the answer to x2 4x 12?
If you are looking to factor this expression, then it does not have a real solution.
