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Earn +20 ptsQ: What is the equation of a parabola with the vertex of 2 -1?
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A parabola has a vertex at -3 -2 what is its equation?
-1
What could be the equation of the parabola centered at the vertex?
f(x)=x^2
The vertex of the parabola below is at the point 1 3 and the point 4 4 is on the parabola What is the equation of the parabola?
(y - 3) = a(x - 1)2 y = a(x - 1)2 + 3 4 = a(4 - 1)2 + 3 1 = 9a a = 1/9 y = 1/9 (x - 1)2 + 3
What is the standard form of the equation of the parabola with vertex 00 and directrix y4?
Assuming the vertex is 0,0 and the directrix is y=4 x^2=0
How do you find the vertex of the parabola given by y equals -3x2 plus 12x-1?
-3x2+12x-1 = y Solve the quadratic equation when y = 0 by means of the quadratic equation formula which gives x values of 3.914854216 and 0.085145784. Add these values together and divide them by 2 which is 4/2 = 2 and this is the line symmetry of the parabola. Substitute 2 for x into the original equation to find the value of y: So the vertex is at (2, 11) Remember that the parabola has a maximum value because the coefficient of x2 is negative in other words it will face downwards.
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