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Find the slope and intercepts of each line y equals -x plus 1000?
Slope: -1 intercepts: (0,1000),(1000,0)
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
What is the X and Y intercepts for 2x plus y equals 1?
y intercept is 1 x intercept is .5
What is the length of the circle radus if the quation for the circle is x2 plus y2 equals 1?
The ' 1 ' in that equation is the radius.
How do you find the x-intercept for x2 36 plus y2 64 equals 1?
The x intercept is where y = 0. Substituting the value y = 0 into this equation gives: 36x2 = 1 x2 = 1/36 x = +- 1/6 So the intercepts are (1/6, 0) and (-1/6, 0)
Find the slope and intercepts of each line y equals -x plus 1000?
Slope: -1 intercepts: (0,1000),(1000,0)
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
What is the X and Y intercepts for 2x plus y equals 1?
y intercept is 1 x intercept is .5
What is the length of the circle radus if the quation for the circle is x2 plus y2 equals 1?
The ' 1 ' in that equation is the radius.
How do you find the x-intercept for x2 36 plus y2 64 equals 1?
The x intercept is where y = 0. Substituting the value y = 0 into this equation gives: 36x2 = 1 x2 = 1/36 x = +- 1/6 So the intercepts are (1/6, 0) and (-1/6, 0)
How do you find the x intercept for x2 36 plus y2 64 equals 1?
It seems that it is the equation of an ellipse, x2/b2 + y2/a2 = 1, with center at the origin, a vertical major axis with length 2a, and a horizontal minor axis with length 2b. x2/36 + y2/64 = 1 Since you are looking for the x-intercepts, they are (√b2, 0) = (√36, 0) = (6, 0) and (-√b2, 0) = (-√36, 0) = (-6, 0)
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
Is equation is x2 plus y2 equals 1 what is the circles radius?
Proper form first. X2 + Y2 = 1 Y2 = 1 - X2 Y = (+/-) sqrt(1 - X2) -------------------------- zero out the X Y = (+/-) sqrt(1 - 02) Y = 1 ----------------the radius of this circle
How do you find the point of intersection between x2 plus y2 equals 5 and x-y equals 1?
x-y = 1 => x = y+1 x2+y2 = 5 => (y+1)(x+1)+y2 = 5 2y2+2y-4 = 0 y = -2 or y = 1 So the points of intersection are: (-1, -2) and (2, 1)
Find the centre and radius of the circle with equation x2 plus 2x plus y2 equals 12?
x2 + 2x + y2 = 12 (complete the square)(x2 + 2x + 1)+ y2 = 12 + 1(x + 1)2 + y2 = 13 (divide by 13 each element to both sides)(x + 1)2/13 + y2/13 = 1(x - -1)2/13 + (y - 0)2/13 = 1Thus, the center of the circle is (-1, 0) and its radius is 1.
What is the length of the circle radius if the circle is x2 plus y2 equals 1?
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
What is the solution to x2 plus 2y-6x plus 8y-1 equals x2-y2 plus 4x-6y-1?
x2 + 2y - 6x + 8y - 1 = x2 - y2 + 4x + 6y - 1 y2 - 10x + 4y = 0 y(y+4) = 10x It cannot be solved completely because with two variables (x and y) you need two independent equations for a full solution.
