-3
y = -x2 - 4x - 3. The constant, 3, tells us where the graph would hit the y-axis. In this case, it would hit the y-axis at -3. Solving the equation y = -(x2 + 4x + 3) ; y=-(x+3)(x+1) Therefore hits the x-axis at -3 and -1. Since it's a parabola (x2), the graph can either start from the top, or from the bottom. An equation starting with ax2 will start from the top, and an equation with -ax2 will start from the bottom. So therefore, the graph starts from the bottom of the page, goes from -3 and -1 on the x-axis and intercepts the y-axis at -3.
4x-2y = 3 -2y = -4x+3 y = 2x-1.5 in slope intercept form
For 4x + 2y = 6The X intercept is 1.5The Y intercept is 3
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
-3
3
y = -x2 - 4x - 3. The constant, 3, tells us where the graph would hit the y-axis. In this case, it would hit the y-axis at -3. Solving the equation y = -(x2 + 4x + 3) ; y=-(x+3)(x+1) Therefore hits the x-axis at -3 and -1. Since it's a parabola (x2), the graph can either start from the top, or from the bottom. An equation starting with ax2 will start from the top, and an equation with -ax2 will start from the bottom. So therefore, the graph starts from the bottom of the page, goes from -3 and -1 on the x-axis and intercepts the y-axis at -3.
4x - 3y = -6Add 3y to each side:4x = -6 + 3yAdd 6 to each side:4x + 6 = 3yDivide each side by 3:(4/3)x + 2 = yThe graph is a straight line with a slope of (4/3) and a y-intercept of 2 .
x2 + 4x + 3 = (x + 1)(x + 3)
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.
4x-2y = 3 -2y = -4x+3 y = 2x-1.5 in slope intercept form
3y - 4x = 24 The first step is to write it in the standard form (y=mx + c) 3y = 4x + 24 y = (4x + 24)/3 y = 4x/3 + 8 The y-intercept is 8 and the slope/gradient is 4/3
For 4x + 2y = 6The X intercept is 1.5The Y intercept is 3
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0