(-1.2,0),(1.2,0)
v(0, -72)
50x^2-72=0 factor out 2
2(25x^2-36)=0
2(5x+6)(5x-6)=0
x=-6/5 and x=6/5
The average of these two is zero, substitute that into the equation and you get -72.
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Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913
A quadratic polynomial must have zeros, though they may be complex numbers.A quadratic polynomial with no real zeros is one whose discriminant b2-4ac is negative. Such a polynomial has no special name.
Nature Of The Zeros Of A Quadratic Function The quantity b2_4ac that appears under the radical sign in the quadratic formula is called the discriminant.It is also named because it discriminates between quadratic functions that have real zeros and those that do not have.Evaluating the discriminant will determine whether the quadratic function has real zeros or not. The zeros of the quadratic function f(x)=ax2+bx+c can be expressed in the form S1= -b+square root of D over 2a and S2= -b-square root of D over 2a, where D=b24ac.... hope it helps... :p sorry for the square root! i know it looks like a table or something...
For a parabola in a normal position ... with its nose either straight up or straight down ... the x-value of the vertex is midway between the zeros of the function, i.e. their average.
Factoring by the AC method, difference of squares, perfect square trinomial. If not factorable by those ways, you can use the quadratic formula. You can also find zeros by synthetic division. If there are not any real solutions, then the solutions are said to be complex, they do not cross the x axis.