Q: What are the zeros and vertex in this quadratic equation 50x2-72?

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Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913

A quadratic polynomial must have zeros, though they may be complex numbers.A quadratic polynomial with no real zeros is one whose discriminant b2-4ac is negative. Such a polynomial has no special name.

Nature Of The Zeros Of A Quadratic Function The quantity b2_4ac that appears under the radical sign in the quadratic formula is called the discriminant.It is also named because it discriminates between quadratic functions that have real zeros and those that do not have.Evaluating the discriminant will determine whether the quadratic function has real zeros or not. The zeros of the quadratic function f(x)=ax2+bx+c can be expressed in the form S1= -b+square root of D over 2a and S2= -b-square root of D over 2a, where D=b24ac.... hope it helps... :p sorry for the square root! i know it looks like a table or something...

For a parabola in a normal position ... with its nose either straight up or straight down ... the x-value of the vertex is midway between the zeros of the function, i.e. their average.

Factoring by the AC method, difference of squares, perfect square trinomial. If not factorable by those ways, you can use the quadratic formula. You can also find zeros by synthetic division. If there are not any real solutions, then the solutions are said to be complex, they do not cross the x axis.

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First, check to see if the equation can be simplified into bracket form. In this case, it can be simplified to (-x + 3)(-x + 7). These brackets identify the zeroes of the quadratic equation; the vertex is always in the middle of the zeros. To find the zeros, set the brackets equal to zero, and now x = 3, 7. 3+7/2 = 10/2 = 5, so the vertex occurs at x = 5. y at x = 5 is -4, so the vertex is (5, -4).

by synthetic division and quadratic equation

Whether or not a function has zeros depends on the domain over which it is defined.For example, the linear equation 2x = 3 has no zeros if the domain is the set of integers (whole numbers) but if you allow rational numbers then x = 1.5 is a zero.A quadratic function such as x^2 = 2 has no rational zeros, but it does have irrational zeros which are sqrt(2) and -sqrt(2).Similarly, a quadratic equation need not have real zeros. It will have zeros if the domain is extended to the complex field.In the coordinate plane, a quadratic without zeros will either be wholly above the horizontal axis or wholly below it.

Using the quadratic equation formula:- x = -4.706950048 and x = 0.849071913

A quadratic polynomial must have zeros, though they may be complex numbers.A quadratic polynomial with no real zeros is one whose discriminant b2-4ac is negative. Such a polynomial has no special name.

The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.

x2 + 15x +36

Nature Of The Zeros Of A Quadratic Function The quantity b2_4ac that appears under the radical sign in the quadratic formula is called the discriminant.It is also named because it discriminates between quadratic functions that have real zeros and those that do not have.Evaluating the discriminant will determine whether the quadratic function has real zeros or not. The zeros of the quadratic function f(x)=ax2+bx+c can be expressed in the form S1= -b+square root of D over 2a and S2= -b-square root of D over 2a, where D=b24ac.... hope it helps... :p sorry for the square root! i know it looks like a table or something...

you use difference of squaresex. X^2-4 can be factored out to (x+2)(x-2)you now have the zeros in your equation much easier

For a parabola in a normal position ... with its nose either straight up or straight down ... the x-value of the vertex is midway between the zeros of the function, i.e. their average.

Factoring by the AC method, difference of squares, perfect square trinomial. If not factorable by those ways, you can use the quadratic formula. You can also find zeros by synthetic division. If there are not any real solutions, then the solutions are said to be complex, they do not cross the x axis.

y=2x2 + 3x-1 To find the zeros of this equation (when y=0) set the equation = 0 0=2x2 + 3x-1 Now, you can either graph the equation in a graphing calculator and find the x intercepts (where the function crosses the x-axis and y=0) or you can factor the quadratic equation by "smiling" or reverse foiling. However, this equation cannot be easily factored. Therefore, using a graphing calculator will provide the correct answer of x= -1.780776 and x= 0.28077641 You can also use the quadratic formula where the general form of a quadratic equation is ax2 +bx+ c=0=y In order to use the quadratic formula, you simple plug the corresponding values into the x= equation. This will produce the same results as graphing and finding the x intercepts.