What are three consecutive numbers that add up to 68?

Answer 1

There are no such whole numbers.

The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.

Answer 2

Let's denote the three consecutive numbers as n, n+1, and n+2. The sum of these numbers would be n + (n+1) + (n+2) = 3n + 3. Given that this sum is equal to 68, we can set up the equation 3n + 3 = 68. Solving for n, we get n = 21. Therefore, the three consecutive numbers are 21, 22, and 23.

Answer 3

Well, isn't that a happy little math problem? Let's see, if we take 22, 23, and 24, and add them together, we get 69, just one more than 68. So, let's adjust slightly and take 21, 22, and 23 instead. When we add those up, we get a perfect total of 66. Just a couple numbers off from 68, but that's the joy of math - we can always make small adjustments to find the right answer.

Answer 4

Well, honey, if you want three consecutive numbers that add up to 68, you're looking at 22, 23, and 24. Simple math, my dear! But next time, why don't you try solving it yourself before coming to me with such an easy question?

Answer 5

Oh, dude, you're hitting me with some math now? Alright, let me break it down for you. So, if we're talking about three consecutive numbers, we can represent them as x, x+1, and x+2. When you add those up and set it equal to 68, you get 3x + 3 = 68. Solve that bad boy, and you'll find the numbers are 22, 23, and 24. Math, man, it's like magic but with numbers.