They are: 68+69+70 = 20768, 69 and 70.
64 + 66 + 68 = 198
33 & 35.
Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.
207
They are: 68+69+70 = 20768, 69 and 70.
137
The three numbers will have a mean of 204/3 = 68. The two numbers are therefore 66, 68, 70.
66 + 67 + 68
5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 = 68
Answer: The even numbers are 62, 64, 66, and 68
64 + 66 + 68 = 198
The numbers are 33 and 35.
33 & 35.
Let the first even number be x. Then the second even number would be x + 2, and the third even number would be x + 4. The sum of these numbers is x + (x + 2) + (x + 4) = 3x + 6. We set this equal to 204 and solve for x: 3x + 6 = 204 --> 3x = 198 --> x = 66. Therefore, the three consecutive even numbers are 66, 68, and 70.
The idea is to add all three numbers, then divide the result by 3 (because there are 3 numbers).
Here's how you can work it out: First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say: x + (x + 2) + (x + 4) = 210 ∴ 3x + 6 = 210 ∴ 3x = 204 ∴ x = 68 We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together: 68 + 70 + 72 = 210 which confirms our answer.