129+131
260 + ((0 +42 + 45)/3) = 260 + 87/3 = 260 + 29 = 289
260,000,000
All the prime numbers between 230 and 260 are; 233, 239, 241, 251, and 257.
You need at least two numbers to find a GCF.
It is 260.
The numbers are 260, 262 and 264.
129+131
There are four of them, which are 256, 258, 259 and 260.
777/3 = 259. So the numbers are 258, 259 and 260.
260 is a composite, like all even numbers greater than 2.260 is composite.
260, like all even numbers greater than 2, is a composite number.
1000, 1023122434, 1243234 are all even numbers that come after 256. In increasing order the even numbers that immediately follow after 256 are 258, 260, 262, 264, ... In decreasing order, the even numbers that immediately follow 256 are 254, 252, 250, 248, ...
All multiples of 260 (which are infinite) including 260, 520, 780, 1040, 1300 . . .
No, prime numbers must have exactly two divisors which result in an integer dividend; these numbers are one (1) and the number itself. Since 260 is an even number it has two (2) as a such a divisor. Thus, it has more than two and is not prime.
260 + ((0 +42 + 45)/3) = 260 + 87/3 = 260 + 29 = 289
The prime numbers between 230 and 260 are 233, 239, 241, 251, and 257.