Let the two consecutive even integers be (x) and (x + 2). According to the problem, the greater integer (x + 2) is equal to three times the smaller integer (x) minus four, which can be expressed as the equation (x + 2 = 3x - 4). Solving this gives (2 + 4 = 3x - x), leading to (6 = 2x) or (x = 3). However, since we're looking for even integers, we can set (x = 2n) for some integer (n), leading us to the conclusion that the integers are (2n) and (2n + 2). Thus, the specific integers will depend on the value of (n).
The smaller integer is 17.
The numbers are 9 and 10.
x+3 and x+4 would be consecutive integers.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
-1
The smaller integer is 17.
6+7=13 and 6 and 7 are consecutive. 6 is the smaller integer so answer is 6
The two integers are 6 and 7.
The larger integer is 30. The smaller is 28.
The numbers are 9 and 10.
The sum is four.
x+3 and x+4 would be consecutive integers.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
-1
The product of two consecutive positive integers can be found by multiplying the smaller integer by the larger integer. If the smaller integer is represented as ( n ), then the larger integer would be ( n + 1 ). Therefore, the product of two consecutive positive integers is ( n \times (n + 1) ).
No.A positive integer is always larger than a negative integer. In the case of two negative integers, the integer with the larger absolute value is actually smaller.
There can be no such integers: a smaller integer cannot be 5 times the larger number.