48 1/3, 48 2/3, 48 3/3
48 = 6 x 8, so the smaller is 6.
Suppose the first number is 2x (rather than x, so that you force it to be even), where x is an integer. Then the next (consecutive) even number is 2x+2. So the equation is: 2x * (2x+2) = 48
15, 16 and 17
14,16.18
48 1/3, 48 2/3, 48 3/3
Because 6*8 = 48 and 48/8 = 6
48 = 6 x 8, so the smaller is 6.
-17, -16 and -15
The integers are 44, 46 and 48.
Suppose the first number is 2x (rather than x, so that you force it to be even), where x is an integer. Then the next (consecutive) even number is 2x+2. So the equation is: 2x * (2x+2) = 48
15, 16 and 17
14,16.18
No solution. 22 + 24 = 46 24 + 26 = 50
The numbers are -18, -16 and -14.
There is no set of four consecutive odd integers for 204. The only set is even: 48, 50, 52 and 54.
They are 6 times 8 = 48