No solution.
22 + 24 = 46
24 + 26 = 50
They are 6 times 8 = 48
10 and 12
The product of any number of negative integers is positive if there is an even count of them, and negative if there is an odd count. Since 90 is an even number, the product of the 90 negative integers will be positive. When this positive product is multiplied by the 9 positive integers, the overall product remains positive. Therefore, the sign of the product will be positive.
8
48 = 6 x 8, so the smaller is 6.
The product of 2 consecutive positive number is 48. Find the 2 numbers
They are 6 times 8 = 48
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
10 and 12
I think you mean consecutive even integers: 20 & 22
The product of any number of negative integers is positive if there is an even count of them, and negative if there is an odd count. Since 90 is an even number, the product of the 90 negative integers will be positive. When this positive product is multiplied by the 9 positive integers, the overall product remains positive. Therefore, the sign of the product will be positive.
10-11-12
8
48 = 6 x 8, so the smaller is 6.
Find three consecutive positive even integers whose sum is 123 , Answer
12 and 14.
The numbers are 12 and 14.