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What are the two consecutive numbers with a product of 7310?
Let the number be 'n' & 'n+1' ; consecutive. Hence n(n+1) = 7310 ( product) n^(2) + n = 7310 Complete the Square ( n + 1/2)^(2) - (1/2)^(2) = 7310 ( n + 1/2)^2 - 1/4 = 7310 (n + 1/2)^(2) = 7310.25 Square root both sides n+ 1/2 = +/- 85.5 (NB 1/2 = 0.5) n = 85.5 - 0.5 = 85 Hence n + 1 = 86 Verification 85 X 86 = 7310
Find two consecutive numbers with a product of 4160?
Find two consecutive numbers with the value of 4160
What one-digit number is the product of two consecutive prime numbers?
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
What two consecutive numbers have a product of 10712?
The numbers are 103 and 104.
What two consecutive numbers have a product of 4160?
The numbers are 64 and 65.
