How about: 36+64 = 100
64 and 36.
If a question says solve the sum of the squares of 3 and 10, you would multiply 3 by 3 to get 9 and 10 by 10 to get 100, and add the two numbers to get 109. 32 + 102 = 9 + 100 = 109
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
82 + 102 = 64 + 100 = 164
64 and 36.
36 and 64
Two Numbers are 8 and 6. This is how. 8 + 6 = 14 and 8*8 + 6*6 = 64 + 36 = 100
36 and 64
The sum of their squares is 10.
If a question says solve the sum of the squares of 3 and 10, you would multiply 3 by 3 to get 9 and 10 by 10 to get 100, and add the two numbers to get 109. 32 + 102 = 9 + 100 = 109
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
62 + 82 = 36 + 64 = 100
Let the numbere be 'n' & 'm' Hence the square of their sum is (m + n)^(2) Add the two numbers together , then square them . The sum of their squares is n^(2) + m^(2) Verification Let m' & 'n' be '5' & '6' Hence Their sum squared is ( 5 + 6) ^(2) = 11^(2) = 121 However square them and them add. 5^(2) + 6^(2) = 25 + 36 = 61 A completely different numerical answer!!!!!
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
82 + 102 = 64 + 100 = 164
It is Fermat's theorem on the sum of two squares. An odd prime p can be expressed as a sum of two different squares if and only if p = 1 mod(4)