36 and 64
Two Numbers are 8 and 6. This is how. 8 + 6 = 14 and 8*8 + 6*6 = 64 + 36 = 100
The sum of their squares is 10.
102 + 32 = 100 + 9 =109 (not an even number)
Sum of squares? Product?
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
How about: 36+64 = 100
64 and 36.
Two Numbers are 8 and 6. This is how. 8 + 6 = 14 and 8*8 + 6*6 = 64 + 36 = 100
36 and 64
The sum of their squares is 10.
If a question says solve the sum of the squares of 3 and 10, you would multiply 3 by 3 to get 9 and 10 by 10 to get 100, and add the two numbers to get 109. 32 + 102 = 9 + 100 = 109
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
62 + 82 = 36 + 64 = 100
8081 can be the sum of two perfect squares because its perfect squares are 41 x41+80x80=1681+6400. Answer=1681+6400
82 + 102 = 64 + 100 = 164
It is Fermat's theorem on the sum of two squares. An odd prime p can be expressed as a sum of two different squares if and only if p = 1 mod(4)
102 + 32 = 100 + 9 =109 (not an even number)