ways of getting 14 1,1,6,6 6 arrangements (1,6,1,6; 1,6,6,1; 1,1,6,6; 6,6,1,1; 6,1,6,1; 6,1,1,6) 1,2,5,6 24 arr. 1,3,4,6 24 arr. 1,3,5,5 12 arr. 1,4,4,5 12 arr. 2,2,4,6 12 arr. 2,2,5,5 6 arr. 2,3,3,6 12 arr. 2,3,4,5 24 arr. 2,4,4,4 4 arr. 3,3,3,5 4 arr. 3,3,4,4 6 arr. Total: 146 146*(1/6)4 = 0.1127... so slightly over 1/9
formula for arr- total room revenue ARR= ------------------------------ total occupied room
No. All rhombi (rhombuses) are parallelograms but all parallelograms are not rhombi.
No but all parallelograms are trapezoids
No, but all parallelograms are trapezoids.
$arr=array(2,5,4,6,7,8,1); for($i=0;$i<count($arr);$i++) { for($j=$i;$j<count($arr);$j++) { if($arr[$i] > $arr[$j]) { $temp=$arr[$i]; $arr[$i]=$arr[$j]; $arr[$j]=$temp; } } }
No arr refers to address of array &arr refers address of address of array but compiler treats arr and & arr, so even you place arr and & arr no error only warnings will be displayed.
Yes, 'ARR' and 'ARR' are the same for char20. Whatever it means.
for example:int arr[3];arr[0] = 1; /* ok */arr[1] = 2; /* ok */arr[2] = 0; /* ok */arr[3] = -1; /* wrong */arr[-1] = -3; /* wrong */
ways of getting 14 1,1,6,6 6 arrangements (1,6,1,6; 1,6,6,1; 1,1,6,6; 6,6,1,1; 6,1,6,1; 6,1,1,6) 1,2,5,6 24 arr. 1,3,4,6 24 arr. 1,3,5,5 12 arr. 1,4,4,5 12 arr. 2,2,4,6 12 arr. 2,2,5,5 6 arr. 2,3,3,6 12 arr. 2,3,4,5 24 arr. 2,4,4,4 4 arr. 3,3,3,5 4 arr. 3,3,4,4 6 arr. Total: 146 146*(1/6)4 = 0.1127... so slightly over 1/9
9, the elements are: arr[0], arr[1], ... arr[9]
ARR = Average Room Revenue
How to caculated arr at front office
If the calculated ARR is greater that the predetermined ARR then accept the project. otherwise reject the project
formula for arr- total room revenue ARR= ------------------------------ total occupied room
No trapezoids are parallelograms, and no parallelograms are trapezoids.
No trapezoids are parallelograms, and no parallelograms are trapezoids.