6 6*6=36 8*6+48
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To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
When it is a multiple of 12 such as 24, 36, 48, etc.
12
12, 24, 36, 48 - the multiples of 12.
22 / 24, 33 / 36, 44 / 48, etc. Notice how the numerator is always divisible by 11 and the denominator is divisible by 12.