It is: 36 and so 960/48 = 20
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
2
Itself
It is: 1056+2 = 1058 and 1058/23 = 46
10056÷23 gives 437 as quotient and 5 as remainder. Dividend-remainder= divisor× quotient so 10056-5=23×437 gives 10051.our question is least no should be added to 10056 which is divisible by 23. Check next possibility 23×438 gives 10074. Now 10056+18= 10074. Therefore 18 is the least number should be added to 10056 to get a number divisible by 23
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
To find the least number that must be added to 37969 to make it exactly divisible by 65, first, we calculate the remainder when 37969 is divided by 65. The remainder is 44 (since 37969 ÷ 65 = 584 with a remainder of 44). To make it divisible by 65, we need to add (65 - 44 = 21). Thus, the least number that must be added is 21.
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
It is 20 because 5220/180 = 29
3.5 !
It is 8961 - W*int(8961/W)
9400÷65 gives144 quotient,40 remainder. 65×145 =9425 25 is the least
the least number is 210 which is divisible by four different prime numbers.
To find the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63, we need to find the least common multiple (LCM) of these four numbers. The LCM of 42, 49, 56, and 63 is 1764. To make 3500 divisible by 1764, we need to find the remainder when 3500 is divided by 1764, which is 1972. Therefore, the least number that should be added to 3500 to make it divisible by 42, 49, 56, and 63 is 1764 - 1972 = 208.
2
Itself