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It is not opssible to give a sensible answer to this question. 46+58 = 104. So if the class has 46% girls and 58% boys then the class has 4% who are simultaneously girls and boys.
From the given information, one can infer that the subject is in a class of 11 people. In addition, he has the median height among all students in his class.
Still working on the test. At first glance you know that at least one third of the class is still working on it (half the girls are one third of the class). And since over half the boys have finished, you know the total remaining is less than half. You can figure it out using any numbers to set it up, but let's use 20 girls and 10 boys as the simplest. So 10 girls and 8 boys have finished for a total of 18, which leaves 12 still working on it. 12/30 is 6/15ths which is 2/5ths which is the same as 40%.
the trick for working ratio and proportions out is to,eg, say if there 5 girls in a class and the ratio of how many boys was 5:1 there will be 25 boys because you simply have to do 5x5=25 then simply times it by one .i think
this is 15/91