What determines the theoretical throughput of a bus
If measurements are taken for two (or more) variable for a sample , then the correlation between the variables are the sample correlation. If the sample is representative then the sample correlation will be a good estimate of the true population correlation.
Evidence that there is no correlation.
They can be positive correlation, negative correlation or no correlation depending on 'line of best fit'
Yes it can be a correlation coefficient.
effective bandwidth
Bandwidth is the measure of range or band of frequencies that a channel or path can handle at a maximum rate. whereas, throughput is the average rate of successful message delivery over a communication channel. and Goodput is simply the changing in throughput rate.
Outbound throughput simply describes the data bandwidth that a network device can send using. Kinda like a sustained upload speed.
People often confuse bandwidth and throughput. 802.11a and 802.11g are the two common standards that have a maximum bandwidth of 54Mbps. The actual maximum throughput you will see on a 54Mbps link will be 20-25Mbps.
bandwidth
Firewire 800 has twice the bandwidth of the Firewire 400.The number is the throughput in Megabits.
D. 802.11n boasts a mximum throughput of 600 mbps.
A trunk port is a port on a switch that can be assigned to carry multiple VLANs across switches or increase overall bandwidth/throughput.
Processor / bus frequency has no direct correlation to bandwidth.
Throughput in megabits per second will always be equal to or less than the bandwidth in megabits per second (it can't be higher). Throughput decreases as latency increases. For instance if you send a file to your neighbor two houses down the latency should be very low (assuming you are on the same network). However, if you send it to another city the latency will be higher and while your bandwidth remains the same, your throughput will decrease due to the latency between the locations. Note that this can be improved by optimizing the TCP window size on your computers. There is a free TCP optimizer program available on the web if you search on that term.
Hai, first STM stands for (Synchronous Transport Modules) it is nothing but the bandwidth Throughput, STM1 = 155.52Mbps there for for STM4 = STM1 * 4 ie = 155.52 * 4, there fore STM4 = 622Mbps, Thanks & Regards Ashok Sriram DEN NETWORKS BANGALORE
The main reason is that even when the full channel bandwidth is used there is always overhead required to manage the information transfer, so some of the total bandwidth will be consumed by this overhead. So only the remaining bandwidth is potentially available for throughput. This is true for both digital and analog communication channels. An example of overhead present in both digital and analog telephone communication channels are "alarm" signals used to report equipment failures to assist in equipment maintenance. Some examples of overhead in computer network channels are start bits, stop bits, parity bits, CRC codes, sync bytes, and packet headers. Also in many situations the traffic load is low for long periods of time so in those periods much of the potentially available throughput will not be made use of.