The expression (2a + 2b) can be factored to represent (2(a + b)), indicating that it is twice the sum of the variables (a) and (b). This formula could represent various concepts depending on the context, such as the total combined value of two quantities (a) and (b) multiplied by two, or the perimeter of a rectangle with length (a) and width (b). It highlights the idea of scaling the sum of two quantities.
P = 2a + 2b Where a & b are the sides of the parallelogram.
(a - 2b)(2a - b)
6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -36 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -36 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -36 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -3
You need to solve the two equations P = perimeter A = area B = width H = height P = 2B + 2H A = BH H = A/B P = 2B + 2A/B P = (2B^2 + 2A)/B 2B^2 -PB +2A = 0 use quadratic formula B = (P +/- SQRT(P^2-16A))/4 ONE ROOT IS B, the other is H
1
a-^2a-b^-a-b
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
P = 2a + 2b Where a & b are the sides of the parallelogram.
(a - 2b)(2a - b)
2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b
6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -36 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -36 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -36 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2bAdding the two equations gives: 18 = 9a so that a = 2Substituting for a in the first gives 12 = 6 - 2b so that b = -3
2(a+b) is 2a plus 2b in factored form.
It is 2a-b simplified
2a
Well if you are adding you would have 8a+2b subtract you would have -2a+2b
You need to solve the two equations P = perimeter A = area B = width H = height P = 2B + 2H A = BH H = A/B P = 2B + 2A/B P = (2B^2 + 2A)/B 2B^2 -PB +2A = 0 use quadratic formula B = (P +/- SQRT(P^2-16A))/4 ONE ROOT IS B, the other is H
Do this: write it out 2 |2a + 4b + 8 Now what divides into all the numbers? ---------------- a + 2b + 4 answer is 2(a+2b+4)