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Any number greater than or equal to 4*sqrt(48) = 27.71 cm (approx).
Let the length, L, be any number greater than sqrt(48) = 6.93 cm (approx)
and let W = 48/L cm.
Then Area = L*W = L*48/L = 48 cm2
But since L can have an infinite number of values, so can the perimeter.
For example,
L = 48, W = 1, A = 48 and P = 98
L = 96, W = 0.5, A = 48 and P = 193
L = 480, W = 0.1, A = 48 and P = 960.2
L = 960, W = 0.05, A = 1 and P = 1920.1
L = 4800, W = .01, A = 48 and P = 9600.02
there is no limit to the size of P.
What else can I help you with?
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The perimeter of a rectangle cannot be determined with the area alone as the lengths could vary. For example, the perimeter of the rectangle could be 12 (1 and 5) or 9 (2 and 2.5). For both cases, the area is still 5cm2, but the length can still change to result in different results.
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What is the greatest perimeter 48cm2 could have?
To find the shape with the greatest perimeter for a given area, we look at the properties of geometric shapes. Among all shapes, a circle has the maximum perimeter for a given area. However, since 48 cm² is a fixed area, the rectangle with the largest perimeter has its dimensions approaching a line segment (as one side becomes very long and the other very short). Therefore, the greatest perimeter would occur with extreme aspect ratios, which can theoretically approach infinity as the dimensions diverge.
What is the perimeter of a rectangle has an area of 5cm square?
The perimeter of a rectangle cannot be determined with the area alone as the lengths could vary. For example, the perimeter of the rectangle could be 12 (1 and 5) or 9 (2 and 2.5). For both cases, the area is still 5cm2, but the length can still change to result in different results.
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