They first has a greater probability. This is because the first digit comes from a set of 9: {1,2,3,4,5,6,7,8,9} while the second comes from that same set AND 0.
There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.
4 Every digit between the leftmost non-zero digit and EITHER the right most non-zero digit OR the rightmost digit after a decimal.
The period of a 5 digit number comes between the ones place and the tenths place. If there is no period, it is assumed to come to the right of the right-most digit. That would make it a whole number. For example, 1256.9 is one thousand, two hundred fifty six and nine tenths. 3.4582 is three and four thousand, five hundred, eighty two ten thousandths.
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?
By including the number 1000, the digit 1.
1-301 times
The digit 1 appears 301 times, as opposed to 300 for the digits 2 to 9.
They first has a greater probability. This is because the first digit comes from a set of 9: {1,2,3,4,5,6,7,8,9} while the second comes from that same set AND 0.
It is the digit 8.
There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.
4 Every digit between the leftmost non-zero digit and EITHER the right most non-zero digit OR the rightmost digit after a decimal.
The single-digit that appears most frequently between and including the numbers 1 and 1000 is the digit "1". To see why this is the case, consider the following pattern: Between 1 and 9, there is one occurrence of the digit "1". Between 10 and 99, there are 10 occurrences of the digit "1" in the tens place (10, 11, 12, ..., 19) and 9 occurrences of the digit "1" in the ones place (21, 31, 41, ..., 91), for a total of 19 occurrences. Between 100 and 999, there are 100 occurrences of the digit "1" in the hundreds place (100, 101, 102, ..., 199), 100 occurrences of the digit "1" in the tens place (110, 111, 112, ..., 119, 121, 131, ..., 191, 201, ..., 291, 301, ..., 391, ..., 901, ..., 991) and 9 occurrences of the digit "1" in the ones place (101, 111, 121, ..., 191), for a total of 210 occurrences. Adding up the number of occurrences for each range, we get: 1 + 19 + 210 = 230 Therefore, the digit "1"
The period of a 5 digit number comes between the ones place and the tenths place. If there is no period, it is assumed to come to the right of the right-most digit. That would make it a whole number. For example, 1256.9 is one thousand, two hundred fifty six and nine tenths. 3.4582 is three and four thousand, five hundred, eighty two ten thousandths.
The answer between 1 and 1000 is 840, but what about 1 and 1100?
Larry csonka
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?