Use some method which you probably already learned, to find the least common multiple. All the other common multiples are multiples of this least common multiple, so you can multiply the least common multiple by 2, by 3, by 4, etc., to get additional common multiples.
2 and 5 are the prime factors that are common to all multiples of 10.
Each common multiple of 9 and 10 occurs exactly once (in the list of common multiples), so there is no common multiple that occurs the most. All common multiples of 9 and 10 are the multiples of their least common multiple which is 90.
The common multiples of 3,4, and 10 would be all the multiples of 60. 60, 120, 180, 240... all the way to 6000.
20 pinkgal333:20, 40, 60 are all common multiples.
Common multiples of 9 and 10 are all of the multiples of 90.
Use some method which you probably already learned, to find the least common multiple. All the other common multiples are multiples of this least common multiple, so you can multiply the least common multiple by 2, by 3, by 4, etc., to get additional common multiples.
2 and 5 are the prime factors that are common to all multiples of 10.
Each common multiple of 9 and 10 occurs exactly once (in the list of common multiples), so there is no common multiple that occurs the most. All common multiples of 9 and 10 are the multiples of their least common multiple which is 90.
The common multiples of 3,4, and 10 would be all the multiples of 60. 60, 120, 180, 240... all the way to 6000.
Common three-digit multiples of 27 and 11 are 297, 594 and 891. None of their digits add up to 10.
100, 110 and 120 are 3 digit multiplies of 10.
20 pinkgal333:20, 40, 60 are all common multiples.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 926 is a 6 which is NOT a 0, so 936 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
All the common multiples of a set of numbers are the multiples of their lowest common multiple: lcm(5, 8, 10) = 40 → first three common multiples are 40, 80, 120